An irregularly shaped piece of gold was lowered into a graduated cylinder holding a volume of water equal to 17 ml. The height of the water rose to 20 ml. If the mass of the gold was 27 g, what was its density?.

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9 g/cm³ is density If the mass of the gold was 27 g,

1 ml = 1 cm³

water volume = 17 mL

water rose  height = 20 mL

gold  Volume= 20 - 17 = 3 mL or 3 cm³

chain weighs 27g ;displaces 3 cm³ of water

chain  Specific density​= chain weight / Volume of water displaced

chain  Specific density​ = 27/ 3

chain  Specific density​ = 9

gold Specific density​ = 9

gold density​ = 9 g/cm³

The mass of a material substance per unit volume is known as density.  Density is often measured in grams per cubic centimeter. For instance, water has a density of 1 grams per cubic centimeter, compared to Earth's density of 5.51 grams. The kilograms per cubic meter unit is another method to express density (in meter-kilogram-second or SI units)

To know more about  density visit : https://brainly.com/question/952755

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