Relax

Respuesta :

TPS00
A line parallel to y = 0.6x + 3 will be of the form:

[tex]y = 0.6x + k[/tex]

where k is a constant.

It passes through (-3,-5)

Thus,

[tex]y = 0.6x + k \\ \\ -5 = 0.6 \times (-3) + k \\ \\ -5 = -1.8 + k \\ \\k = -5 + 1.8 \\ \\ k = -3.2[/tex]

[tex]\textbf{The equation is \: \: y = 0.6x - 3.2} [/tex]

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