ΔH fusion of water is 6.0 kJ/mol mass of ice = 35.1 g Molecular weight of water = 18.015 g / mole number of moles of water = 35.1 / 18.015 = 1.95 mole amount of heat required to melt ice = moles * Δ H fusion = 1.95 x 6 =11.7 kJ mass of water at 25°C required to get this energy to a temperature 0°C q = m C ΔT 11700 J = m * 4.184 * (25°- 0°) m = 111.85 g
