22-03-2018
Chemistry

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what mass of anhydrous solute is needed to prepare 2.25L of 0.141 M K2SO4 (aq)? answer in units of g

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mandylim66p30240 mandylim66p30240

22-03-2018

M= mol/L
So mol = 2.25L(.141M) = .317mol

Molar mass of K2SO4 = 174.259g

Stoich:
.317mol(174.259g) = 46.7g

Ans: 46.7g

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