I found some missing information about this problem online. We are given the force: [tex] F = F =(-7.50N)i +(3.00N)j[/tex] Power is defined as the rate of doing work. This is the formula: [tex]P= \frac{dW}{dt} [/tex] Where P is power, W is work. Work is defined as: [tex]W=F\cdot r[/tex] F is the force and r is the displacement. If we assume that force is not changing (it's constant) with time we get: [tex]P= \frac{dW}{dt}=F \frac{dr}{dt}=F\cdot v [/tex] Keep in mind that both force and velocity are vectors, so we have to multiply each component separately. Finally, we get: [tex]P=F_i\cdot v_i+F_j\cdot v_j=(-7.50N)(3.40\frac{m}{s})+(3.00N)(2.20\frac{m}{s})=
-18.9 W[/tex]
