
Respuesta :
√c^2+2c-4=√1-2c
 raising both members to the square
 c^2+2c-4=1-2c
 rewriting
 c^2+4c-5=0
 factoring
 (c+5)*(c-1)=0
 the solutions for this case re
 c=-5
 c=1
 the answer isÂ
 Both –5 and 1 are true solutions
 raising both members to the square
 c^2+2c-4=1-2c
 rewriting
 c^2+4c-5=0
 factoring
 (c+5)*(c-1)=0
 the solutions for this case re
 c=-5
 c=1
 the answer isÂ
 Both –5 and 1 are true solutions