23-04-2014
Physics

contestada

A dart is thrown horizontally with an initial speed of 10 m/s toward point P, the bull's-eye on a dart board. It hits at point Q on the rim, vertically below P, 0.19 s later.
(a) What is the distance ?
(b) How far away from the dart board is the dart released?

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mtresley mtresley

23-04-2014

D=s(t) so it would be d=10(.19) d=.19 FOR BITH SNDWERS

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