4. Thorium-234 has a half-life of 24.1 days. What percentage of the original thorium-234 in a sample will remain after 144.6 days?

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Respuesta :

how many half lives have elapsed?
actually the formula is like this
A=P(1/2)^(t/h)
P=iniital amount
t=time
h=half life
A=final amount
so

hmm, percent
so P=1 then
A=1(1/2)^(144.6/24.1)
A=1(1/2)^6
A=1/64
A=0.05625
so 5.625% is left