Probability theory predicts that there is a 56.6% chance of a particular basketball player making 5 free throws in a row. If the basketball player taking 5 free throws is simulated 5000 times, in about how many of the simulations would you expect at least 1 missed free throw?

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the answer is 2170 that is the answer for apex



Answer with explanation:

It is given that ,According to Probability theory Β there is a 56.6% chance of a particular basketball player making 5 free throws in a row.

If, Number of throws=5,000

So, number of throws in which basketball player will make 5 free throws

Β  Β  =56.6 % of 5,000

Β  Β [tex]=\frac{56.6}{100}\times 5000=2830[/tex]

Number of Simulation , in which the basketball player can have at least 1 missed free throw

Β = 5000-2830

=2170