cynthiadiazavila cynthiadiazavila
  • 26-04-2017
  • Chemistry
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What volume of 0.115 M HCl is required to completely neutralize 0.025 L of 0.138 M KOH?

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Relebi
Relebi Relebi
  • 26-04-2017
0.115V=0.025 x 0.138

0.115V=0.00345

V=0.03
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