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Classify the solutions of 3 over x plus 5, plus one fifth, equals 2 over x plus 5 as extraneous or non-extraneous.
x = −5; extraneous
x = −5; non-extraneous
x = −10; extraneous
x = −10; non-extraneous

Classify the solutions of 3 over x plus 5 plus one fifth equals 2 over x plus 5 as extraneous or nonextraneous x 5 extraneous x 5 nonextraneous x 10 extraneous class=
Relax

Respuesta :

XxLostAndBrokenxX
3/(x + 5) + 1/5 = 2/(x + 5)

1/(x + 5) + 1/5 = 0

1/(x + 5) = -1/5

5 = -(x + 5)

5 = -x - 5

10 = -x

x = -10

x = - 10; non-extraneous

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