baileysmall
contestada

1.) What is the vertex of the quadratic function y=x^2-4x-1
2.) What is the solution set for the quadratic function y=x^2-4x-21
3.) What are the solutions to the quadratic equation (x+9)(x-1)=0
4.) What are the zeros for the quadratic function f(x)=x^2+10+25

Relax

Respuesta :

calebwhitaker
1.  Solve by differentiation (Derivative = 0 at the vertex)

dy/dx= 2x-4

0=2x-4

0=2(x-2)

x=2

when x=2 y=-5

therefore vertex (2,-5)
Ver imagen calebwhitaker

Otras preguntas