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A jet taxiing down the runway receives word that it must return to the gate. The jet is traveling 34.5 m/s when the pilot receives the message. What is the acceleration of the plane if it takes the pilot 6.48 s to bring the plane to a halt?

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Answer:

- 5.32 m/s^2

Explanation:

vo = original velocity = 34.5 ┬аm/s

vf = final velocity = 0

t = 6.48 s

vf = vo ┬а+ at

0 = 34.5 + a (6.48)

a = - 5.32 m/s^2 ┬а ┬а<=====NOTE: ┬аa negative acceleration is a DEcceleration

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