
7250 gms is the minimum mass of ethylene glycol required to prevent the solution from freezing.
A liquid's freezing point is the temperature at which it turns into a solid. Similar to the melting point, the freezing point typically rises with increasing pressure.
Given;
We are aware that a colligative property of depression in freezing point depends on molality as.
In order to have a freezing point of -12.0°F means we need a depression in freezing point to be −24.4°c
we know that depression in freezing point is a colligative property which depends on molality as
depression in freezing point = Kf X molality
Kf = 1.86 °C/m
molality = moles of solute / mass of solvent in Kg
15 = 1.86 °C/m X molality
molality = 8.065
molality = moles of glycerol / mass of water in Kg
moles of glycerol = 8.065 X 14.5
moles = 116.9425
moles = mass / molar mass
mass = moles X molar mass = 116.9425 X 62 = 7250 grams
7250 gms is the minimum mass of ethylene glycol required to prevent the solution from freezing.
Learn more about the Freezing point with the help of the given link:
brainly.com/question/3121416
#SPJ4