Company A offers $38,000 initial salary with an $1,000 annual raise. Company B offers $24,000 initial salary with an $8,000 annual raise. After how many years will you have the same salary? What will that salary be? Please hurry it’s urgent. Also please add an step by step explanation.

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Answers:

After how many years will you have the same salary? After 2 years.

What will that salary be? $40,000.

Step-by-step explanation:

1. Find equations for each company's salary.

Let's create equation that give the salary with respect to time.

For company A, the function of salary is:

[tex]S(t)=1000x+38000[/tex], where x is the time in years.

For company B, the function of salary is:

[tex]S(t)=8000x+24000[/tex], where x is the time in years.

2. Create a system of equations.

For this questions, we must set up a system of linear equations to see where the 2 lines of these equations meet. This will give us the point where both salary and time are the same in the 2 companies.

[tex]\left \{ {{S(t)=1000x+38000} \atop {S(t)=8000x+24000}} \right.[/tex]

3. Solving the system of equations,

a. Write the functions in terms of x and y.

[tex]1.y =1000x+38000\\ \\2. y=8000x+24000[/tex]

b. Equal the expressions.

[tex]1000x+38000=8000x+24000[/tex]

c. Solve for x.

[tex]1000x+38000=8000x+24000\\ \\1000x-8000x=24000-38000\\ \\-7000x=-14000\\ \\x=\frac{-14000}{-7000} \\ \\x=2[/tex]

d. Use the x value in any of the functions to obtain y.

[tex]y=8000(2)+24000\\ \\y=40000[/tex]

4. Interpret the results.

The point where the 2 functions meet is (2,40000), this means that 2 years after the person joins any of the companies they will have the same salary. This salary will be $40,000.

Answer:

2 years

$40,000

Step-by-step explanation:

Given information:

  • Company A offers $38,000 initial salary with an $1,000 annual raise.
  • Company B offers $24,000 initial salary with an $8,000 annual raise.

Define the variables

  • Let x = number of years
  • Let y = total annual salary

Create two equations with the given information and defined variables:

[tex]\begin{cases}y = 38000 + 1000x\\y = 24000 + 8000x\end{cases}[/tex]

To find after how many years the salary will be the same, substitute the second equation into the first equation and solve for x:

[tex]\implies 24000+8000x = 38000+1000x[/tex]

Subtract 1000x from both sides:

[tex]\implies 24000+8000x-1000x = 38000+1000x-1000x[/tex]

[tex]\implies 24000+7000x = 38000[/tex]

Subtract 24000 from both sides:

[tex]\implies 24000+7000x -24000 = 38000-24000[/tex]

[tex]\implies 7000x = 14000[/tex]

Divide both sides by 7000:

[tex]\implies \dfrac{7000x}{7000} = \dfrac{14000}{7000}[/tex]

[tex]\implies x = 2[/tex]

Therefore, the number of years after which the salaries will be the same is 2 years.

To find what the salary will be, substitute x = 2 into one of the equations and solve for y:

[tex]\implies 38000 + 1000(2) = 38000+2000=40000[/tex]

Therefore, the salary after 2 years will be $40,000.

Learn more about systems of equations here:

https://brainly.com/question/27520807

https://brainly.com/question/27868619

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