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Jaxon is flying a kite, holding his hands a distance of 3.25 feet above the ground and letting all the kite’s strings play out. He measures the angle of elevation from his hand to the kite to be 24∘. If the string from the kite to his hand is 105 feet long, how many feet is the kite above the ground? Round your answer to the nearest tenth of a foot if necessary.

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Medunno13

Answer: 46.0 ft

Step-by-step explanation:

[tex]\sin 24^{\circ}=\frac{x}{105}\\\\x=105\sin 24^{\circ}[/tex]

So, the distance above the ground is [tex]105\sin 24^{\circ}+3.25 \approx \boxed{46.0 \text{ ft}}[/tex]

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