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Yo! Solving linear equations with integers! These are just some practice exercises I need help with! So they should probably be simple, I need these done asap, I’d appreciate work shown C:
1) - 4 + 3x = 4 x - 8
2) -5x - 8 = 2
3) 12 r - 14 = 5 ( 2 - r )
4) 3 x - 8 = - ( 17 + 2x)
Ty!

Yo Solving linear equations with integers These are just some practice exercises I need help with So they should probably be simple I need these done asap Id ap class=
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Respuesta :

devishri1977

Answer:

Step-by-step explanation:

Solving linear equation with one variable:

   1) -4 + 3x = 4x - 8

        Add 4 to both sides

      -4 + 3x + 4 = 4x - 8 +  4

               3x     = 4x - 4

Subtract 4x from both sides,

        3x - 4x = -4x + 4x - 4

              -x   = -4

                [tex]\sf \boxed{\bf x = 4}[/tex]

2) -5x - 8 = 2

Add 8 to both sides

 -5x - 8 + 8 = 2 + 8

            -5x  = 10

Divide both sides by (-5)

            [tex]\sf \dfrac{-5}{-5}x =\dfrac{10}{-5}[/tex]

                 [tex]\sf \boxed{\bf x = -2}[/tex]

3) 12r - 14 = 5(2-r)

    12r - 14 = 5*2 - 5*r

     12r - 14 = 10 - 5r

Add 14 to both sides

 12r - 14 + 14 = 10 - 5r + 14

             12r  = 24 - 5r

Add 5r to both sides

        12r + 5r = 24

               17r = 24

Divide both sides by 17

                 r = 24/17

4) 3x - 8 = -(17 + 2x)

  3x - 8 = -17 - 2x

Add 8 to both sides

3x - 8 + 8 = -17 - 2x + 8

           3x = -9 - 2x

Add 2x to both sides

      3x + 2x = -9

            5x  = -9

Divide both sides by 5

              [tex]\sf \dfrac{5}{5}x=\dfrac{-9}{5}\\\\\boxed{x = \dfrac{-9}{5}}[/tex]

sarajeffries7

Answer:

1) x = 4

2) x = -2

3) [tex]r= \frac{24}{7}[/tex]   [tex](1\frac{7}{17})[/tex]

4) [tex]x=-\frac{9}{5}[/tex]  [tex](-1\frac{4}{5})[/tex]

Step-by-step explanation:

hope this helps!!

(work shown in photo :)  )

Ver imagen sarajeffries7

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