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For each of the following acid-base titration combinations , determine the number of moles of the first substance listed that would be the chemically equivalent amount of the second substance.

a. NaOH with 1.0 mol HCL
b. HNO3 with 0.75 mol KOH
c. Ba(OH) with 0.20 mol HF
d. H2SO4 with 0.90 mol Mg(OH)2
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1.0 mol HCl will require 1.0 mol NaOH, 0.75 mol KOH will require 0.75 mol [tex]HNO_3[/tex],  0.20 mol HF will require 0.1 mole [tex]Ba(OH)_2[/tex], and 0.90 mol [tex]Mg(OH)_2[/tex] will require 0.90 mole [tex]H_2SO_4[/tex]

What are mole ratios?

It is the ratio of the chemical components in chemical reactions.

The equation for each of the listed reactions is as follows:

  • NaOH + HCl ---------> NaCl + [tex]H_2O[/tex]
  • [tex]HNO_3 + KOH ----- > KNO_3 + H_2O[/tex]
  • [tex]Ba(OH)_2 + 2HF ------ > BaF_2 +2 H_2O[/tex]
  • [tex]H_2SO_4 + Mg(OH)_2 ---- > MgSO_4 + 2H_2O[/tex]

The mole ratio of NaOH and HCl is 1:1, that of  [tex]HNO_3[/tex] and KOH is also 1:1, that of  [tex]Ba(OH)_2[/tex] and HF is 1:2, and that of [tex]H_2SO_4[/tex] and [tex]Mg(OH)_2[/tex] is 1:1.

Thus, 1.0 mol HCl will require 1.0 mol NaOH, 0.75 mol KOH will require 0.75 mol [tex]HNO_3[/tex],  0.20 mol HF will require 0.1 mole [tex]Ba(OH)_2[/tex], and 0.90 mol [tex]Mg(OH)_2[/tex] will require 0.90 mole [tex]H_2SO_4[/tex]

More on mole ratios can be found here: https://brainly.com/question/15288923

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