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a A force of 100N is required to stretch a string that obeys Hooks law by 50cm. What is the work done in stretching the spring?​

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princechimezirim096

Answer:

[tex]workdone \: in \: stretching \: a \: spring \: = \frac{1}{2}ke {}^{2} \\ workdone = \frac{1}{2}fe \\ beause \: f = ke \\ f = 1000 \: \: x = 50cm \: = 0.5m \\ w = \frac{1}{2} (100)(0 .5) { }^{2} \\w = 12.5 \: newtonpermetre[/tex]

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