27. The perimeter of a rectangle is 46 inches. If the width of the rectangle is 11 inches, what is
the length?

A. 12 in
B. 23 in
C. 35 in
D. 24 in

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Answer:

12

Step-by-step explanation:

perimeter is (a+b) x 2 = 46

a is width and b is length

a=11

(11+b) x 2 = 46

22 + 2b = 46

2b = 24

b = 12 ( length )

Solution:

We know that:

  • Width of rectangle = 11 inches
  • Perimeter of rectangle = L + B + L + B = 2L + 2B

Substitute the width in the expression:

  • 2L + 2B = Perimeter
  • 2L + 2(11) = 46 in

Simplify the LHS:

  • 2L + 22 = 46 in

Subtract 22 both sides:

  • 2L = 46 - 22
  • 2L = 24

Divide 2 both sides:

  • 2L/2 = 24/2
  • L = 24/2 = 12 in