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indrawboy

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N₂ (g) + 3 H₂ (g) ---> 2 NH₃ (g)

mol NH₃ = H₂ (limited reactant) :

[tex]\tt \dfrac{2}{3}\times 9=6~moles[/tex]

grams: mol x Mr NH₃ (17 g/mol):

[tex]\tt = 6\times 17=102~g[/tex]

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