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Part C
Using the reaction you just successfully chose in the last problem, assuming that you have 30.0 grams of solid magnesium and an excess amount of HCI, how
much magnesium chloride would you produce?
The balanced equation is

Mg + 2HCI -> H2 + MgCl2

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Respuesta :

Eduard22sly

The mass of magnesium chloride, MgClâ‚‚ obtained from the reaction is 118.75 g

Determination of the mass of Mg and MgClâ‚‚ from the balanced equation.

We'll begin by calculating the mass of Mg that reacted and the mass of MgClâ‚‚ obtained from the balanced equation

Mg + 2HCI —> H₂ + MgCl₂

Molar mass of Mg = 24 g/mol

Mass of Mg from the balanced equation = 1 × 24 = 24 g

Molar mass of MgCl₂ = 24 + (35.5×2) = 95 g/mol

Mass of MgCl₂ from the balanced equation = 1 × 95 = 95 g

SUMMARY

From the balanced equation above,

24 g of Mg reacted to produce 95 g of MgClâ‚‚.

Determination of the mass of MgClâ‚‚ produced from the reaction.

From the balanced equation above,

24 g of Mg reacted to produce 95 g of MgClâ‚‚.

Therefore,

30 g of Mg will react to produce = (30 × 95) / 24 = 118.75 g of MgCl₂.

Thus, 118.75 g of MgClâ‚‚ were obtained from the reaction.

Learn more about stoichiometry:

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