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a constant current flows in the conductor with a magnitude of 1.6 mA. Calculate the charge and number of electrons transferred through the straight cross-section of the conductor in 1 hour.

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Respuesta :

  • Current=1.6mA=1.6×10^{-3}A=0.0016A=I
  • Time=1h=3600s=t
  • Charge=Q

[tex]\\ \sf\longmapsto I=\dfrac{Q}{t}[/tex]

[tex]\\ \sf\longmapsto Q=It[/tex]

[tex]\\ \sf\longmapsto Q=0.0016(3600)[/tex]

[tex]\\ \sf\longmapsto Q=5.76C[/tex]

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