
9514 1404 393
Answer:
 5.6 miles
Step-by-step explanation:
Let the following distances between exits be defined:
 a = exit 5 to 6
 b = exit 6 to 7
 c = exit 7 to 8
Then the given relations are ...
 a = 3.2
 b = 1.1 +a = 4.3
 (b +c) = 2.4 +(a +b)  ⇒  c = a +2.4 = 5.6
The distance between exits 7 and 8 is 5.6 miles.