For the hydraulic jack of the Figure 3.32, a force of 100 lb is exerted on the small piston. Determine the upward force on the large piston. The diameter of the small piston is 2 in and the diameter of the large piston is 6 in.

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Answer:

112 lb

Explanation:

Multiply 2x6 and then add 100 and 12 which gives you 112 pounds