A spinner is divided into 4 equal sections numbered 1 through 4. It is spun twice, and the numbers from each spin are added.

What is the probability that the sum is less than 6?

0.563
0.714
0.625
0.750

Relax

Respuesta :

Answer:

0.625

Step-by-step explanation:

Since there are 4 options each time the spinner is spun, there are a total of [tex]4\cdot 4=16[/tex] non-distinct sums possible when we spin it twice.

Out of these, the possible sums that meet the condition (less than 6) are 2, 3, 4, and 5 (since the smallest sum possible is 1+1=2).

Count how many ways there are to achieve each of these sums:

[tex]1+1=2\\\\1+2=3\\2+1=3\\\\2+2=4\\1+3=4\\3+1=4\\\\2+3=5\\3+2=5\\4+1=5\\1+4=5[/tex]

Totally there are 10 ways to achieve a sum less than 6. Therefore, the desired probability is [tex]\frac{10}{16}=\frac{5}{8}=\boxed{0.625}[/tex]