Answer:
the film's minimum thickness to make the reflected light enhanced in brightness is 112.8 nm
Explanation:
Given the data in the question;
wavelength λ = 600 nm
index of refraction = 1.33
so the film's minimum thickness to make the reflected light enhanced in brightness = ?
condition for maxima for reflected light is;
2nt = [ ( 2m + 1 )λ ] / 2
we solve for t
4nt = [ ( 2m + 1 )λ ]
t = [ ( 2m + 1 )λ ] / nt
Now, for minimum thickness m = 1
t = λ / 4n
so we substitute in our values;
t = 600 nm / ( 4 × 1.33 )
t = 600 nm / 5.32
t = 112.78195 ≈ 112.8 nm { one decimal place }
Therefore, the film's minimum thickness to make the reflected light enhanced in brightness is 112.8 nm
