Answer:
Step-by-step explanation:
Let n = 1. Then:
2 + 22 + 23 + 24 + ... + 2n = 21 = 2
...and:
2n+1 – 2 = 21+1 – 2 = 22 – 2 = 4 – 2 = 2
So (*) works for n = 1.
Assume, for n = k, that (*) holds; that is, that
2 + 22 + 23 + 24 + ... + 2k = 2k+1 – 2
Let n = k + 1.
