A four digit number (with no repetitions) is to be formed from the set of numbers {0,1,2,3,4,5,6,7}. Find the probability that the number
a) is even
b) is odd
c) is less than 4000
d) is less than 4000, given that it is greater than 3000

Relax

Respuesta :

even # --------- if it ends with 0, # of ways = 6*5*4 = 120 if not, 3 ways for ending digit, 5 ways for 1st digit, 5*4 for middle digits = 300 
so total ways = 420 
odd # --------- 4 ways of ending digit, 5 ways for 1st digit, 5*4 for middle digits = 400 ways 
< 4000: ---------- 3 ways for starting digit, 6*5*4 ways for remaining digits = 360 ways 
> 3000 & < 4000 ------------------------ 1 way for starting digit , 6*5*4 for remaining digits = 120 ways