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A 40.0 kg crate is being lowered by means of a rope. Its downward acceleration is 3.80 m/s2. What is the force exerted by the rope on the crate? A 40.0 kg crate is being lowered by means of a rope. Its downward acceleration is 3.80 m/s2. What is the force exerted by the rope on the crate?

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MissPhiladelphia
Newton's Second Law of Motion states, “The force acting on an object is equal to the mass of that object times its acceleration.” We calculate as follows:

F = ma =40.0 kg (- 3.80 m/s^2) = -152 J

NOTE: It has a negative sign due to the direction of acceleration.
Hope this answers the question. Have a nice day.

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