21-11-2016
Mathematics

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solve system by substitution method 3x+2y-z=23, y=8, -2y+4z=16 showing step by step this is algebra 2

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21-11-2016

X=5
Y=8
Z=8

3x+2y-z=23 --> z=-23+2y+3x
Y=8
Substitute for -2y+4z=16

-2(8)+4(-23+2(8)+3x)=16
-16-28+12x=16
-44+12x=16
12x=60
X=5

Substitute known y and x values into z=-23+2y+3x

Z=-23+2(8)+3(5)
Z=-23+16+15
Z=8

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