acute198911 acute198911
  • 23-02-2021
  • Mathematics
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A^3=5 b^3=4 Find value of (ab^2)^-3 ​

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clarch19
clarch19 clarch19
  • 24-02-2021

Answer:

1/80

Step-by-step explanation:

(ab²)^-3 = (a^-3)(b^-6) = [tex]\frac{1}{5}[/tex]b^6

[tex]\frac{1}{5}[/tex]b^6 = 1 /[5(b³)²] = 1 / (5·4²)  = 1/80

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