What volume of chlorine gas (Cl2), measured at STP, can be produced by the decomposition of 73.0g of hydrogen chloride gas (HCl), according to the balanced equation? (the other product is hydrogen gas (H2))

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Answer:

Explanation:

2HCl    =   H₂   +   Cl₂

2 mole     1 mole      1 mole

73 gram HCl = 73 / 36.5 = 2 mole of HCl

2 moles of HCl will produce 1 mole of chlorine gas .

At STP , one mole of chlorine gas has volume equal to 22.4 litre .