24-01-2021
Mathematics

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Find three consecutive integers such that the sum of the first and twice the second is 68 minus three times the third.

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anonymousagain anonymousagain

24-01-2021

Answer:

x=9.5

Step-by-step explanation:

x+2(x+1)=68-3(x+3)

x+2x+2=68-3x-9

3x+2=68=59-3x

6x=57

x=9.5

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