One father is 70 inches tall and the residual for his son’s height is 2.5. What is the son’s actual height?

71.7 inches
74.2 inches
76.7 inches
82.3 inches

Relax

Respuesta :

Answer: C

Step-by-step explanation:

Since the heights of the men are assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = heights of the men.

µ = mean height

σ = standard deviation

From the information given,

µ = 70.7 inches

σ = 2.1 inches

The probability that they have a mean height greater than 71.7 inches is expressed as

P(x > 71.7) = 1 - P(x ≤ 71.7)

For x = 71.7

Since n = 36, then

z = (71.7 - 70.7)/2.1/√36 = 2.86

Looking at the normal distribution table, the probability corresponding to the z score is 0.998

P(x > 71.7) = 1 - 0.998 = 0.002

Answer:

the answer is 74.2

Step-by-step explanation:

i just took the test and got it right