If the track has circumference c miles, then and the car's speeds are x and y mi/s, then since time = distance/speed,Β
In the same direction, the slow car has a "lead" of 1 mile which the faster car has to make up.Β
1/(y-x) = 120Β
1/(x+y) = 30Β
120(y-x) = 30(x+y)Β
120y-120x = 30x+30yΒ
90y = 150xΒ
y = 5/3 xΒ
1/(x + 5/3 x) = 30Β
8/3 x * 30 = 1Β
80x = 1Β
x = 1/80 mi/sec = 45 mphΒ
y = 75 mph