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A coffee mixture contains beans that sell for $0.08 per pound and $0.32 per pound. if 110 pounds of beans create a mixture that sells for $0.27 per pound, to the nearest tenth of a pound, how much of each bean is used in the mixture? model the scenario with an equation and solve. use complete sentences to explain whether or not your solution is reasonable.

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Respuesta :

syed514
bean A is 0.08/pound
bean B is 0.32/pound
A+B=110
.08A+0.32(B)=29.7 comes from the mixture of 110 pounds at 0.27/pound
A=110-B
0.08(110-B)+0.32B=29.7

8.8-0.08B+0.32B=29.7
0.24B=20.9
B=87.1 pounds at 0.32=27.87
A=22.9 pounds at0.08=1.83

10 pounds with a dollar value of $29.70, which is $0.27 per pound 
hope this helps

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