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Ammonia, NH3, is a common ingredient in many household cleaning agents. If you have a cleaning agent containing 2.07 mol NH3, how many grams of NH3 are in the cleaning agent?
I don't understand how to set this problem. I know to start with 2.07 then multiply up I'm stuck the rest of the way

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JoshEast
In order to do this question you have to first know the relationship between moles (g) and mass (g) ;  Mass = Mole  ×  Molar Mass

if mole of NH₃ = 2.07 mol
and Molar Mass of NH₃  =  [14 + (3 × 1)] g/mol

then mol  =  2.07 mol  × 17 g/mol
                =  35.19 g
tutorAnne

There are 35.19grams in the the cleaning agent NH3.

Finding the mass of NH3

The relationship between mass, moles and molar mass is given by

Number of moles  = Mass/ Molar mass

Given that the

  • Number of moles fond in NH3  is 2.07 mol
  • Molar mass will now be NH₃  =  [14 + (3 × 1)] g/mol  =17g/mol

Therefore Mass of NH3  =Number of moles x Molar mass

=35.19g

Learn more on calculations on finding mass here:L https://brainly.com/question/21921960

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