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If 17.8 g grams of lithium (Li) are combined with 50.0 grams of water (H20) there is
24.7 grams of hydrogen gas (H2) produced. How much lithium hydroxide (LiOH) was
also produced?

Relax

Respuesta :

Answer:

Explanation:

Li+H2O..................LiOH+H2

mass of Li=17.8 g

No of moles of Li=17.8/7=2.5

mass of H2O=50.0 g

No of moles of H2O=50.0/18=2.8

limiting reagent is Li so 1 mole of Li produce 1 mole of LiOH therefore 2.5 mole of Li produce 2.5 moles of LiOH now we have to convert it into grams

moles=given mass/molar mass

given mass=moles*molar mass

molar mass of LiOH=24

mass=2.5*24=60 gram