
Answer:
The nth term will be;
Tn = Tn-1 + 6(n-2) + 11
Step-by-step explanation:
Here, we are to find the nth term of the given equation
Firstly, we need to notice a pattern
What difference do we notice between the terms?
That would be;
16-5 = 11
33-16 = 17
56-33 = 23
next would be 29 + 56 = 85
afterwards; 85 + 35 = 120
So the pattern here is that we shall add 6 to the last common difference between the two preceding term to get the succeeding term
So what’s the nth term here?
Tn = Tn-1 + 6(n-2) + 11
So for example, the 5th term will be;
T5 = T5 + 6(5-2) + 11
T5= 56 + 18 + 11 = 85
While the 4th term will be
T4 = 33 + 6(4-2) + 11
T4 = 33 + 12 + 11 = 33 + 23 = 56