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(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 ⋅ 2^28 (5 points)

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AMIM14

Answer:

Step-by-step explanation:

(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3

(2^8 ⋅ 3^−5 ⋅ 6^0)^−6

(a^m)^n=a^m*n

So,

(2^8*-6) * (3^−5*-6) * (6^0*-6)

(2^-48) (3^30) (6^0)

a^0=1

So,

(2^-48) (3^30) (1)

(2^-48) (3^30)

I hope this helps you friend!

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