sonusoul21 sonusoul21

21-07-2020
Chemistry

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Volume occupied 3.52x10^32 moluchles
of Mathane (CH4)
1) At STP

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nobleswift nobleswift

21-07-2020

Answer:

volume = 13097674418.528dm³

Explanation:

n = (3.52)*10^32/(6.02)*10^23)

n = (584717607.97)

n = volume /molar volume

molar volume at stp = 22.4dm³

volume= 584717607.97 x 22.4

volume = 13097674418.528dm³

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