
Respuesta :
Answer:
Explanation:
Zn(s) + Cuāŗ( aq) ā ZnāŗĀ²( aq ) + Cu(s)
In oxidation reaction of an element or ion , the oxidation number is increased . Oxidation no is total charge on the atom or ion
In the following half reaction Zn(s) is oxidised to ZnāŗĀ²
Zn( s ) ā ZnāŗĀ²(aq) Ā + 2eā»
In this reaction charge on Zn(s) is zero
After reaction charge on formed ZnāŗĀ² is +2 . Hence there is increase in oxidation number from 0 to + 2 . Hence Zn(s) is oxidised to ZnāŗĀ² ion . Ā