caro12345100 caro12345100

23-06-2020
Mathematics

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Please help . I’ll mark you as brainliest if correct!

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Alfpfeu Alfpfeu

23-06-2020

Answer:

[tex]\boxed{\ g(x)=\dfrac{1}{4}|x-2|+1 \ }[/tex]

Step-by-step explanation:

As the graph is passing via (2,1) and (-6,3)

[tex]g(x)=\dfrac{1}{4}|x-2|+1[/tex]

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