phebe146 phebe146

22-06-2020
Mathematics

contestada

Now look at this information
[tex]2y + 3 \leqslant 11[/tex]

What is the largest value that y could be?

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jimrgrant1 jimrgrant1

22-06-2020

Answer:

4

Step-by-step explanation:

Given

2y + 3 ≤ 11 ( subtract 3 from both sides )

2y ≤ 8 ( divide both sides by 2 )

y ≤ 4

Since y has to be less than or equal to 4

Then the largest value y could be is 4

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