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Given the quadrant of q in standard position and a trigonometric function value of q , find the exact value for the indicated function. II, sin q = 0.4; sec q

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sqdancefan

9514 1404 393

Answer:

  -(5/21)√21

Step-by-step explanation:

In the second quadrant, the cosine and secant are negative, so the value of interest is ...

  sec(q) = -1/√(1 -0.4²) = -1/√0.84 = -√(25/21)

  sec(q) = (-5√21)/21

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