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  • 25-04-2020
  • Mathematics
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DeanR
DeanR DeanR
  • 25-04-2020

f(n) = n² + 20

f(1) = 1² + 20 = 21

f(2) = 2² + 20 = 24

f(3) = 3² + 20 = 29

f(4) = 4² + 20 = 36

f(5) = 5² + 20 = 45

f(6) = 6² + 20 = 56

a) first three terms

Answer: 21, 24, 29

b) how many < 50

f(5)=45, f(6)=56 so

Answer: 5

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