A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600.mL at 1.0atm. To prepare for ignition of the fuel, a piston moves within the cylinder, reducing the volume of the air‑fuel mixture to 50.mL at constant temperature. Assuming ideal behavior, what is the new pressure of the air‑fuel mixture?

Relax

Respuesta :

12 atm is the new pressure of the air‑fuel mixture when A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600 ml at 1.0atm and final volume of 50 ml.

Explanation:

Data given:

The air fuel mixture is assumed to be having ideal behaviour

initial volume of gaseous air fuel mixture V1 = 600 ml

initial pressure of gaseous air fuel mixture P1= 1 atm

final volume when piston is removed, V2= 50 ml

final pressure of the gaseous air mixture, P2 = ?

Applying the Boyle's Law,

P1V1 = P2V2

rearranging the equation:

P2 = [tex]\frac{P1V1}{V2}[/tex]

putting the value in the equation,

P2 = [tex]\frac{600 X 1}{50}[/tex]

P2 = 12 atm

the pressure is increased to 12 atm when volume is reduced to 50 ml.