Relax

Respuesta :

The equation of a circle with center [tex](x_0,y_0)[/tex] and radius [tex]r[/tex] is

[tex](x-x_0)^2+(y-y_0)^2=r^2[/tex]

In your case,

[tex]x_0=3,\quad y_0=-2,\quad r=3[/tex]

Plug these values into the generic formula and you'll get your equation.

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