
Answer:
A) 11223450 J
B) 18705750 J
Explanation:
Work done = force x distance moved.
Force of fluid at bottom of the pool = pghA
Where
P = density of water = 1000 kg/m3
g = acceleration due to gravity = 9.8 m/s2
h = depth of water = 1.5 m
A = area of pool of diameter d = 18 m
A = (¶d^2)/4 = (3.142 x 18^2)/4 = 254.5 m2
Total wall height of pool = 3 m
Force on pool bottom due to water is
F = 1000 x 9.8 x 1.5 x 254.5 = 3741150 N
A) work (in Joules) required to pump all of the water over the side
Height of wall H = 3 m
Work = F x H = 3741150 x 3 = 11223450 J
B) work (in Joules) required to pump all of the water out of an outlet 2m over the side?
Total height will be 2 + 3 = 5 m
Work = F x H = 3741150 x 5 =
18705750 J